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- Phillip Knight wrote:
-
- > class ologstream : public ostream {
- > public:
- [ ... ]
- > ologstream& operator<< (foo &bar)
- > { return *this; } // do nothing
- > };
-
- [ main() then attempts to use ologstream::operator<< on char*]
-
- > on by ostream/ologstream operators. The presence of an operator<<
- > (overloaded or otherwise) in the dervided class consequently hides the base
- > class operators which are public. My question is; is this a bug in the
- > language [...] ?
-
-
- I believe this is the expected behavior for the language.
- You can call the base class version with:
-
- out.ostream::operator<< ("Test one.");
-
- Or (perhaps better depending on how "natural" you want the
- char * version to feel) give ologstream a member:
-
- ologstream& operator<< (char *str)
- { ostream::operator(str); return *this; }
-
-